Best way to encode and decode parameter in springboot

Posted on March 4, 2024

You must create an HTTP entity and send the headers and parameter in body.

@GetMapping(value = "/request")
public String request()  {
    String url =  "http://127.0.0.1:8080/example";
    System.out.println(url);
    RestTemplate restTemplate = new RestTemplate(); 
    HttpHeaders headers = new HttpHeaders();
    headers.setContentType(MediaType.APPLICATION_FORM_URLENCODED);
    MultiValueMap<String, String> map= new LinkedMultiValueMap<String, String>();
    map.add("param","ello&test");
    map.add("id","ab&c=def");
    HttpEntity<MultiValueMap<String, String>> request = new HttpEntity<MultiValueMap<String, String>>(map, headers); 
    return restTemplate.postForObject(url, request, String.class);
}

or
The POST method should be sent along the HTTP request object. And the request may contain either of HTTP header or HTTP body or both.

Hence let's create an HTTP entity and send the headers and parameter in body.

HttpHeaders headers = new HttpHeaders();
headers.setContentType(MediaType.APPLICATION_FORM_URLENCODED);

MultiValueMap<String, String> map= new LinkedMultiValueMap<String, String>();
map.add("email", "first.last@example.com");

HttpEntity<MultiValueMap<String, String>> request = new HttpEntity<MultiValueMap<String, String>>(map, headers);

ResponseEntity<String> response = restTemplate.postForEntity( url, request , String.class );
http://docs.spring.io/spring/docs/current/javadoc-api/org/springframework/web/client/RestTemplate.html#postForObject-java.lang.String-java.lang.Object-java.lang.Class-java.lang.Object...-